4(3^2x+1)+17^x-7=0

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Solution for 4(3^2x+1)+17^x-7=0 equation: 



4(3^2x+1)+17^x-7=0

We multiply parentheses

12x^2+17^x+4-7=0

We add all the numbers together, and all the variables

12x^2+17^x-3=0

We move all terms containing x to the left, all other terms to the right

12x^2+17^x=3

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